@typescript-eslint/no-unnecessary-type-constraint

A type parameter without a constraint already accepts every type. <T extends unknown> and <T extends any> say the same thing with more words.

This rule is on by default in TypeScript files.

Configure

On by default as a warning. To turn it off:

[lint.rules]
"@typescript-eslint/no-unnecessary-type-constraint" = "off" # or "error"

Examples

Reported:

function first<Item extends unknown>(items: Item[]) {
  return items[0];
}

class Box<Value extends any> {
  constructor(public value: Value) {}
}

type Pair<Left, Right extends unknown> = [Left, Right];

Not reported:

function first<Item>(items: Item[]) {
  return items[0];
}

class Box<Value> {
  constructor(public value: Value) {}
}

function longest<Item extends { length: number }>(a: Item, b: Item) {
  return a.length >= b.length ? a : b;
}

In a .tsx file, <Item>(item: Item) => item reads as a JSX tag. Write a trailing comma instead of extends unknown:

const identity = <Item,>(item: Item) => item;